Optimal. Leaf size=165 \[ \frac {x^2 \left (2 a c e-b (c d+a f)-\left (2 c^2 d-b c e+b^2 f-2 a c f\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {\left (4 a c^2 e+b^3 f-2 b c (c d+3 a f)\right ) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{2 c^2 \left (b^2-4 a c\right )^{3/2}}+\frac {f \log \left (a+b x^2+c x^4\right )}{4 c^2} \]
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Rubi [A]
time = 0.19, antiderivative size = 165, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {1677, 1658,
648, 632, 212, 642} \begin {gather*} \frac {x^2 \left (-\left (x^2 \left (-2 a c f+b^2 f-b c e+2 c^2 d\right )\right )-b (a f+c d)+2 a c e\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {\tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right ) \left (-2 b c (3 a f+c d)+4 a c^2 e+b^3 f\right )}{2 c^2 \left (b^2-4 a c\right )^{3/2}}+\frac {f \log \left (a+b x^2+c x^4\right )}{4 c^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 632
Rule 642
Rule 648
Rule 1658
Rule 1677
Rubi steps
\begin {align*} \int \frac {x^3 \left (d+e x^2+f x^4\right )}{\left (a+b x^2+c x^4\right )^2} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {x \left (d+e x+f x^2\right )}{\left (a+b x+c x^2\right )^2} \, dx,x,x^2\right )\\ &=\frac {x^2 \left (2 a c e-b (c d+a f)-\left (2 c^2 d-b c e+b^2 f-2 a c f\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}-\frac {\text {Subst}\left (\int \frac {2 a e-\frac {b (c d+a f)}{c}-\frac {\left (b^2-4 a c\right ) f x}{c}}{a+b x+c x^2} \, dx,x,x^2\right )}{2 \left (b^2-4 a c\right )}\\ &=\frac {x^2 \left (2 a c e-b (c d+a f)-\left (2 c^2 d-b c e+b^2 f-2 a c f\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {f \text {Subst}\left (\int \frac {b+2 c x}{a+b x+c x^2} \, dx,x,x^2\right )}{4 c^2}-\frac {\left (4 a c^2 e+b^3 f-2 b c (c d+3 a f)\right ) \text {Subst}\left (\int \frac {1}{a+b x+c x^2} \, dx,x,x^2\right )}{4 c^2 \left (b^2-4 a c\right )}\\ &=\frac {x^2 \left (2 a c e-b (c d+a f)-\left (2 c^2 d-b c e+b^2 f-2 a c f\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {f \log \left (a+b x^2+c x^4\right )}{4 c^2}+\frac {\left (4 a c^2 e+b^3 f-2 b c (c d+3 a f)\right ) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c x^2\right )}{2 c^2 \left (b^2-4 a c\right )}\\ &=\frac {x^2 \left (2 a c e-b (c d+a f)-\left (2 c^2 d-b c e+b^2 f-2 a c f\right ) x^2\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {\left (4 a c^2 e+b^3 f-2 b c (c d+3 a f)\right ) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{2 c^2 \left (b^2-4 a c\right )^{3/2}}+\frac {f \log \left (a+b x^2+c x^4\right )}{4 c^2}\\ \end {align*}
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Mathematica [A]
time = 0.16, size = 175, normalized size = 1.06 \begin {gather*} \frac {\frac {2 \left (-2 a^2 c f+b \left (c^2 d-b c e+b^2 f\right ) x^2+a \left (b^2 f+2 c^2 \left (d+e x^2\right )-b c \left (e+3 f x^2\right )\right )\right )}{\left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )}+\frac {2 \left (4 a c^2 e+b^3 f-2 b c (c d+3 a f)\right ) \tan ^{-1}\left (\frac {b+2 c x^2}{\sqrt {-b^2+4 a c}}\right )}{\left (-b^2+4 a c\right )^{3/2}}+f \log \left (a+b x^2+c x^4\right )}{4 c^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 228, normalized size = 1.38
method | result | size |
default | \(\frac {\frac {\left (3 a b c f -2 a \,c^{2} e -b^{3} f +b^{2} c e -b \,c^{2} d \right ) x^{2}}{\left (4 a c -b^{2}\right ) c^{2}}+\frac {a \left (2 a c f -b^{2} f +b c e -2 c^{2} d \right )}{\left (4 a c -b^{2}\right ) c^{2}}}{2 c \,x^{4}+2 b \,x^{2}+2 a}+\frac {\frac {\left (4 a c f -b^{2} f \right ) \ln \left (c \,x^{4}+b \,x^{2}+a \right )}{2 c}+\frac {2 \left (-a b f +2 a c e -b c d -\frac {\left (4 a c f -b^{2} f \right ) b}{2 c}\right ) \arctan \left (\frac {2 c \,x^{2}+b}{\sqrt {4 a c -b^{2}}}\right )}{\sqrt {4 a c -b^{2}}}}{2 c \left (4 a c -b^{2}\right )}\) | \(228\) |
risch | \(\text {Expression too large to display}\) | \(1621\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 473 vs.
\(2 (155) = 310\).
time = 0.41, size = 970, normalized size = 5.88 \begin {gather*} \left [\frac {2 \, {\left ({\left (b^{3} c^{2} - 4 \, a b c^{3}\right )} d - {\left (b^{4} c - 6 \, a b^{2} c^{2} + 8 \, a^{2} c^{3}\right )} e + {\left (b^{5} - 7 \, a b^{3} c + 12 \, a^{2} b c^{2}\right )} f\right )} x^{2} - {\left (2 \, a b c^{2} d - 4 \, a^{2} c^{2} e + {\left (2 \, b c^{3} d - 4 \, a c^{3} e - {\left (b^{3} c - 6 \, a b c^{2}\right )} f\right )} x^{4} + {\left (2 \, b^{2} c^{2} d - 4 \, a b c^{2} e - {\left (b^{4} - 6 \, a b^{2} c\right )} f\right )} x^{2} - {\left (a b^{3} - 6 \, a^{2} b c\right )} f\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, c^{2} x^{4} + 2 \, b c x^{2} + b^{2} - 2 \, a c + {\left (2 \, c x^{2} + b\right )} \sqrt {b^{2} - 4 \, a c}}{c x^{4} + b x^{2} + a}\right ) + 4 \, {\left (a b^{2} c^{2} - 4 \, a^{2} c^{3}\right )} d - 2 \, {\left (a b^{3} c - 4 \, a^{2} b c^{2}\right )} e + 2 \, {\left (a b^{4} - 6 \, a^{2} b^{2} c + 8 \, a^{3} c^{2}\right )} f + {\left ({\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} f x^{4} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} f x^{2} + {\left (a b^{4} - 8 \, a^{2} b^{2} c + 16 \, a^{3} c^{2}\right )} f\right )} \log \left (c x^{4} + b x^{2} + a\right )}{4 \, {\left (a b^{4} c^{2} - 8 \, a^{2} b^{2} c^{3} + 16 \, a^{3} c^{4} + {\left (b^{4} c^{3} - 8 \, a b^{2} c^{4} + 16 \, a^{2} c^{5}\right )} x^{4} + {\left (b^{5} c^{2} - 8 \, a b^{3} c^{3} + 16 \, a^{2} b c^{4}\right )} x^{2}\right )}}, \frac {2 \, {\left ({\left (b^{3} c^{2} - 4 \, a b c^{3}\right )} d - {\left (b^{4} c - 6 \, a b^{2} c^{2} + 8 \, a^{2} c^{3}\right )} e + {\left (b^{5} - 7 \, a b^{3} c + 12 \, a^{2} b c^{2}\right )} f\right )} x^{2} - 2 \, {\left (2 \, a b c^{2} d - 4 \, a^{2} c^{2} e + {\left (2 \, b c^{3} d - 4 \, a c^{3} e - {\left (b^{3} c - 6 \, a b c^{2}\right )} f\right )} x^{4} + {\left (2 \, b^{2} c^{2} d - 4 \, a b c^{2} e - {\left (b^{4} - 6 \, a b^{2} c\right )} f\right )} x^{2} - {\left (a b^{3} - 6 \, a^{2} b c\right )} f\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {{\left (2 \, c x^{2} + b\right )} \sqrt {-b^{2} + 4 \, a c}}{b^{2} - 4 \, a c}\right ) + 4 \, {\left (a b^{2} c^{2} - 4 \, a^{2} c^{3}\right )} d - 2 \, {\left (a b^{3} c - 4 \, a^{2} b c^{2}\right )} e + 2 \, {\left (a b^{4} - 6 \, a^{2} b^{2} c + 8 \, a^{3} c^{2}\right )} f + {\left ({\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} f x^{4} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} f x^{2} + {\left (a b^{4} - 8 \, a^{2} b^{2} c + 16 \, a^{3} c^{2}\right )} f\right )} \log \left (c x^{4} + b x^{2} + a\right )}{4 \, {\left (a b^{4} c^{2} - 8 \, a^{2} b^{2} c^{3} + 16 \, a^{3} c^{4} + {\left (b^{4} c^{3} - 8 \, a b^{2} c^{4} + 16 \, a^{2} c^{5}\right )} x^{4} + {\left (b^{5} c^{2} - 8 \, a b^{3} c^{3} + 16 \, a^{2} b c^{4}\right )} x^{2}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 3.72, size = 195, normalized size = 1.18 \begin {gather*} \frac {{\left (2 \, b c^{2} d - b^{3} f + 6 \, a b c f - 4 \, a c^{2} e\right )} \arctan \left (\frac {2 \, c x^{2} + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{2 \, {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} \sqrt {-b^{2} + 4 \, a c}} + \frac {f \log \left (c x^{4} + b x^{2} + a\right )}{4 \, c^{2}} + \frac {2 \, a c^{2} d + a b^{2} f - 2 \, a^{2} c f - a b c e + {\left (b c^{2} d + b^{3} f - 3 \, a b c f - b^{2} c e + 2 \, a c^{2} e\right )} x^{2}}{2 \, {\left (c x^{4} + b x^{2} + a\right )} {\left (b^{2} - 4 \, a c\right )} c^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 2.72, size = 1651, normalized size = 10.01 \begin {gather*} -\frac {\frac {a\,\left (f\,b^2-e\,b\,c+2\,d\,c^2-2\,a\,f\,c\right )}{2\,c^2\,\left (4\,a\,c-b^2\right )}+\frac {x^2\,\left (f\,b^3-e\,b^2\,c+d\,b\,c^2-3\,a\,f\,b\,c+2\,a\,e\,c^2\right )}{2\,c^2\,\left (4\,a\,c-b^2\right )}}{c\,x^4+b\,x^2+a}-\frac {\ln \left (c\,x^4+b\,x^2+a\right )\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )}{2\,\left (256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2\right )}-\frac {\mathrm {atan}\left (\frac {\left (8\,a\,c^3\,{\left (4\,a\,c-b^2\right )}^3-2\,b^2\,c^2\,{\left (4\,a\,c-b^2\right )}^3\right )\,\left (\frac {\frac {\left (8\,a\,f+\frac {8\,a\,c^2\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )}{256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2}\right )\,\left (f\,b^3-2\,d\,b\,c^2-6\,a\,f\,b\,c+4\,a\,e\,c^2\right )}{8\,c^2\,{\left (4\,a\,c-b^2\right )}^{3/2}}+\frac {a\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )\,\left (f\,b^3-2\,d\,b\,c^2-6\,a\,f\,b\,c+4\,a\,e\,c^2\right )}{{\left (4\,a\,c-b^2\right )}^{3/2}\,\left (256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2\right )}}{a\,\left (4\,a\,c-b^2\right )}-x^2\,\left (\frac {\frac {\left (\frac {6\,f\,b^3\,c^2-4\,d\,b\,c^4-28\,a\,f\,b\,c^3+8\,a\,e\,c^4}{4\,a\,c^3-b^2\,c^2}+\frac {\left (8\,b^3\,c^4-32\,a\,b\,c^5\right )\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )}{2\,\left (4\,a\,c^3-b^2\,c^2\right )\,\left (256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2\right )}\right )\,\left (f\,b^3-2\,d\,b\,c^2-6\,a\,f\,b\,c+4\,a\,e\,c^2\right )}{8\,c^2\,{\left (4\,a\,c-b^2\right )}^{3/2}}+\frac {\left (8\,b^3\,c^4-32\,a\,b\,c^5\right )\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )\,\left (f\,b^3-2\,d\,b\,c^2-6\,a\,f\,b\,c+4\,a\,e\,c^2\right )}{16\,c^2\,{\left (4\,a\,c-b^2\right )}^{3/2}\,\left (4\,a\,c^3-b^2\,c^2\right )\,\left (256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2\right )}}{a\,\left (4\,a\,c-b^2\right )}+\frac {b\,\left (\frac {b^3\,f^2-d\,b\,c^2\,f-5\,a\,b\,c\,f^2+2\,a\,e\,c^2\,f}{4\,a\,c^3-b^2\,c^2}+\frac {\left (\frac {6\,f\,b^3\,c^2-4\,d\,b\,c^4-28\,a\,f\,b\,c^3+8\,a\,e\,c^4}{4\,a\,c^3-b^2\,c^2}+\frac {\left (8\,b^3\,c^4-32\,a\,b\,c^5\right )\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )}{2\,\left (4\,a\,c^3-b^2\,c^2\right )\,\left (256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2\right )}\right )\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )}{2\,\left (256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2\right )}-\frac {\left (\frac {b^3\,c^4}{2}-2\,a\,b\,c^5\right )\,{\left (f\,b^3-2\,d\,b\,c^2-6\,a\,f\,b\,c+4\,a\,e\,c^2\right )}^2}{c^4\,{\left (4\,a\,c-b^2\right )}^3\,\left (4\,a\,c^3-b^2\,c^2\right )}\right )}{2\,a\,{\left (4\,a\,c-b^2\right )}^{3/2}}\right )+\frac {b\,\left (\frac {\left (8\,a\,f+\frac {8\,a\,c^2\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )}{256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2}\right )\,\left (-128\,f\,a^3\,c^3+96\,f\,a^2\,b^2\,c^2-24\,f\,a\,b^4\,c+2\,f\,b^6\right )}{2\,\left (256\,a^3\,c^5-192\,a^2\,b^2\,c^4+48\,a\,b^4\,c^3-4\,b^6\,c^2\right )}+\frac {a\,f^2}{c^2}-\frac {a\,{\left (f\,b^3-2\,d\,b\,c^2-6\,a\,f\,b\,c+4\,a\,e\,c^2\right )}^2}{c^2\,{\left (4\,a\,c-b^2\right )}^3}\right )}{2\,a\,{\left (4\,a\,c-b^2\right )}^{3/2}}\right )}{36\,a^2\,b^2\,c^2\,f^2-48\,a^2\,b\,c^3\,e\,f+16\,a^2\,c^4\,e^2-12\,a\,b^4\,c\,f^2+8\,a\,b^3\,c^2\,e\,f+24\,a\,b^2\,c^3\,d\,f-16\,a\,b\,c^4\,d\,e+b^6\,f^2-4\,b^4\,c^2\,d\,f+4\,b^2\,c^4\,d^2}\right )\,\left (f\,b^3-2\,d\,b\,c^2-6\,a\,f\,b\,c+4\,a\,e\,c^2\right )}{2\,c^2\,{\left (4\,a\,c-b^2\right )}^{3/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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